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c^2-9c-1224=0
a = 1; b = -9; c = -1224;
Δ = b2-4ac
Δ = -92-4·1·(-1224)
Δ = 4977
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4977}=\sqrt{9*553}=\sqrt{9}*\sqrt{553}=3\sqrt{553}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{553}}{2*1}=\frac{9-3\sqrt{553}}{2} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{553}}{2*1}=\frac{9+3\sqrt{553}}{2} $
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